-2n^2=-98

Solution for -2n^2=-98 equation:

-2n^2=-98

We move all terms to the left:

-2n^2-(-98)=0

We add all the numbers together, and all the variables

-2n^2+98=0

a = -2; b = 0; c = +98;
Δ = b2-4ac
Δ = 02-4·(-2)·98
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28}{2*-2}=\frac{-28}{-4}
=+7
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28}{2*-2}=\frac{28}{-4}
=-7
$